tty: Simplify tty_release_checks() interface

Passing the 'other' tty to tty_release_checks() only makes sense
for a pty pair; make o_tty scope local instead.

Reviewed-by: Alan Cox <alan@linux.intel.com>
Signed-off-by: Peter Hurley <peter@hurleysoftware.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
Peter Hurley 2014-11-05 12:12:59 -05:00 committed by Greg Kroah-Hartman
parent 62462aefeb
commit 359b9fb5c4

View File

@ -1702,8 +1702,7 @@ static void release_tty(struct tty_struct *tty, int idx)
* Performs some paranoid checking before true release of the @tty.
* This is a no-op unless TTY_PARANOIA_CHECK is defined.
*/
static int tty_release_checks(struct tty_struct *tty, struct tty_struct *o_tty,
int idx)
static int tty_release_checks(struct tty_struct *tty, int idx)
{
#ifdef TTY_PARANOIA_CHECK
if (idx < 0 || idx >= tty->driver->num) {
@ -1722,6 +1721,8 @@ static int tty_release_checks(struct tty_struct *tty, struct tty_struct *o_tty,
return -1;
}
if (tty->driver->other) {
struct tty_struct *o_tty = tty->link;
if (o_tty != tty->driver->other->ttys[idx]) {
printk(KERN_DEBUG "%s: other->table[%d] not o_tty for (%s)\n",
__func__, idx, tty->name);
@ -1777,7 +1778,7 @@ int tty_release(struct inode *inode, struct file *filp)
/* Review: parallel close */
o_tty = tty->link;
if (tty_release_checks(tty, o_tty, idx)) {
if (tty_release_checks(tty, idx)) {
tty_unlock(tty);
return 0;
}