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drm/i915/execlists: Relax the locked clear_bit(IRQ_EXECLIST)
We only need to care about the ordering of the clearing of the bit with the uncached CSB read in order to correctly detect a new interrupt before the read completes. The uncached read itself acts as a full memory barrier, so we do not need to enforce another in the form of a locked clear_bit. v2: Clarify why the split and unlocked test/clear is harmless. Signed-off-by: Chris Wilson <chris@chris-wilson.co.uk> Cc: Tvrtko Ursulin <tvrtko.ursulin@intel.com> Link: http://patchwork.freedesktop.org/patch/msgid/20170323134803.10418-1-chris@chris-wilson.co.uk Reviewed-by: Tvrtko Ursulin <tvrtko.ursulin@intel.com>
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@ -540,7 +540,17 @@ static void intel_lrc_irq_handler(unsigned long data)
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dev_priv->regs + i915_mmio_reg_offset(RING_CONTEXT_STATUS_BUF_LO(engine, 0));
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unsigned int csb, head, tail;
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clear_bit(ENGINE_IRQ_EXECLIST, &engine->irq_posted);
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/* The write will be ordered by the uncached read (itself
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* a memory barrier), so we do not need another in the form
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* of a locked instruction. The race between the interrupt
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* handler and the split test/clear is harmless as we order
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* our clear before the CSB read. If the interrupt arrived
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* first between the test and the clear, we read the updated
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* CSB and clear the bit. If the interrupt arrives as we read
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* the CSB or later (i.e. after we had cleared the bit) the bit
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* is set and we do a new loop.
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*/
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__clear_bit(ENGINE_IRQ_EXECLIST, &engine->irq_posted);
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csb = readl(csb_mmio);
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head = GEN8_CSB_READ_PTR(csb);
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tail = GEN8_CSB_WRITE_PTR(csb);
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