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drivers/char/hpet.c: fix periodic-emulation for delayed interrupts
When interrupts are delayed due to interrupt masking or due to other interrupts being serviced the HPET periodic-emuation would fail. This happened because given an interval t and a time for the current interrupt m we would compute the next time as t + m. This works until we are delayed for > t, in which case we would be writing a new value which is in fact in the past. This can be solved by computing the next time instead as (k * t) + m where k is large enough to be in the future. The exact computation of k is described in a comment to the code. More detail: Assuming an interval of 5 between each expected interrupt we have a normal case of t0: interrupt, read t0 from comparator, set next interrupt t0 + 5 t5: interrupt, read t5 from comparator, set next interrupt t5 + 5 t10: interrupt, read t10 from comparator, set next interrupt t10 + 5 ... So, what happens when the interrupt is serviced too late? t0: interrupt, read t0 from comparator, set next interrupt t0 + 5 t11: delayed interrupt serviced, read t5 from comparator, set next interrupt t5 + 5, which is in the past! ... counter loops ... t10: Much much later, get the next interrupt. This can happen either because we have interrupts masked for too long (some stupid driver goes on a printk rampage) or just because we are pushing the limits of the interval (too small a period), or both most probably. My solution is to read the main counter as well and set the next interrupt to occur at the right interval, for example: t0: interrupt, read t0 from comparator, set next interrupt t0 + 5 t11: delayed interrupt serviced, read t5 from comparator, set next interrupt t15 as t10 has been missed. t15: back on track. Signed-off-by: Nils Carlson <nils.carlson@ericsson.com> Cc: John Stultz <john.stultz@linaro.org> Cc: Thomas Gleixner <tglx@linutronix.de> Cc: Clemens Ladisch <clemens@ladisch.de> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -163,11 +163,32 @@ static irqreturn_t hpet_interrupt(int irq, void *data)
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* This has the effect of treating non-periodic like periodic.
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*/
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if ((devp->hd_flags & (HPET_IE | HPET_PERIODIC)) == HPET_IE) {
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unsigned long m, t;
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unsigned long m, t, mc, base, k;
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struct hpet __iomem *hpet = devp->hd_hpet;
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struct hpets *hpetp = devp->hd_hpets;
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t = devp->hd_ireqfreq;
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m = read_counter(&devp->hd_timer->hpet_compare);
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write_counter(t + m, &devp->hd_timer->hpet_compare);
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mc = read_counter(&hpet->hpet_mc);
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/* The time for the next interrupt would logically be t + m,
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* however, if we are very unlucky and the interrupt is delayed
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* for longer than t then we will completely miss the next
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* interrupt if we set t + m and an application will hang.
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* Therefore we need to make a more complex computation assuming
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* that there exists a k for which the following is true:
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* k * t + base < mc + delta
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* (k + 1) * t + base > mc + delta
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* where t is the interval in hpet ticks for the given freq,
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* base is the theoretical start value 0 < base < t,
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* mc is the main counter value at the time of the interrupt,
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* delta is the time it takes to write the a value to the
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* comparator.
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* k may then be computed as (mc - base + delta) / t .
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*/
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base = mc % t;
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k = (mc - base + hpetp->hp_delta) / t;
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write_counter(t * (k + 1) + base,
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&devp->hd_timer->hpet_compare);
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}
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if (devp->hd_flags & HPET_SHARED_IRQ)
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