video: fbdev: intelfb: Use aperture size from pci_resource_len

Aperture size for i9x5 variants is determined from PCI base address.

	if (pci_resource_start(pdev, 2) & 0x08000000)
		*aperture_size = MB(128);
	...

This condition is incorrect as 128 MiB address can have the address
set as 0x?8000000 or 0x?0000000. Also the code can be simplified to just
use pci_resource_len().

The true settings of the aperture size is in the MSAC register, which
could be used instead. However the value is used only as an info message,
so it doesn't matter.

Signed-off-by: Petr Cvek <petrcvekcz@gmail.com>
Signed-off-by: Helge Deller <deller@gmx.de>
This commit is contained in:
Petr Cvek 2022-06-17 15:38:04 +02:00 committed by Helge Deller
parent fc378794a2
commit 25c9a15fb7

View File

@ -201,13 +201,11 @@ int intelfbhw_get_memory(struct pci_dev *pdev, int *aperture_size,
case PCI_DEVICE_ID_INTEL_945GME:
case PCI_DEVICE_ID_INTEL_965G:
case PCI_DEVICE_ID_INTEL_965GM:
/* 915, 945 and 965 chipsets support a 256MB aperture.
Aperture size is determined by inspected the
base address of the aperture. */
if (pci_resource_start(pdev, 2) & 0x08000000)
*aperture_size = MB(128);
else
*aperture_size = MB(256);
/*
* 915, 945 and 965 chipsets support 64MB, 128MB or 256MB
* aperture. Determine size from PCI resource length.
*/
*aperture_size = pci_resource_len(pdev, 2);
break;
default:
if ((tmp & INTEL_GMCH_MEM_MASK) == INTEL_GMCH_MEM_64M)