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eeepc-laptop: flatten control flow
In eeepc_rfkill_hotplug there's an if statement with a big tail that ends right before the out_unlock label. We might as well invert the condition and jump to out_unlock in that case, pretty much like the rest of the code does. This removes an indentation level for a large chunk of code and also stops suggesting there might be an else clause. Signed-off-by: Frans Klaver <fransklaver@gmail.com> Signed-off-by: Darren Hart <dvhart@linux.intel.com>
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@ -580,7 +580,9 @@ static void eeepc_rfkill_hotplug(struct eeepc_laptop *eeepc, acpi_handle handle)
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mutex_lock(&eeepc->hotplug_lock);
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pci_lock_rescan_remove();
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if (eeepc->hotplug_slot) {
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if (!eeepc->hotplug_slot)
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goto out_unlock;
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port = acpi_get_pci_dev(handle);
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if (!port) {
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pr_warning("Unable to find port\n");
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@ -632,7 +634,6 @@ static void eeepc_rfkill_hotplug(struct eeepc_laptop *eeepc, acpi_handle handle)
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}
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out_put_dev:
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pci_dev_put(port);
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}
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out_unlock:
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pci_unlock_rescan_remove();
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