btrfs: send: remove indirect callback parameter for changed_cb

There's a custom callback passed to btrfs_compare_trees which happens to
be named exactly same as the existing function implementing it. This is
confusing and the indirection is not necessary for our needs. Compiler
is clever enough to call it directly so there's effectively no change.

Reviewed-by: Josef Bacik <josef@toxicpanda.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
David Sterba 2020-08-17 12:16:57 +02:00
parent 8bb1cf1ba6
commit 1b51d6fce4

View File

@ -278,11 +278,6 @@ enum btrfs_compare_tree_result {
BTRFS_COMPARE_TREE_CHANGED,
BTRFS_COMPARE_TREE_SAME,
};
typedef int (*btrfs_changed_cb_t)(struct btrfs_path *left_path,
struct btrfs_path *right_path,
struct btrfs_key *key,
enum btrfs_compare_tree_result result,
void *ctx);
__cold
static void inconsistent_snapshot_error(struct send_ctx *sctx,
@ -6692,8 +6687,7 @@ static int tree_compare_item(struct btrfs_path *left_path,
* If it detects a change, it aborts immediately.
*/
static int btrfs_compare_trees(struct btrfs_root *left_root,
struct btrfs_root *right_root,
btrfs_changed_cb_t changed_cb, void *ctx)
struct btrfs_root *right_root, void *ctx)
{
struct btrfs_fs_info *fs_info = left_root->fs_info;
int ret;
@ -6960,8 +6954,7 @@ static int send_subvol(struct send_ctx *sctx)
goto out;
if (sctx->parent_root) {
ret = btrfs_compare_trees(sctx->send_root, sctx->parent_root,
changed_cb, sctx);
ret = btrfs_compare_trees(sctx->send_root, sctx->parent_root, sctx);
if (ret < 0)
goto out;
ret = finish_inode_if_needed(sctx, 1);