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PCI: Remove useless "!dev" tests
No need to check "!dev" when the caller should always supply a valid pointer. If the caller *doesn't* supply a valid pointer, it probably won't check for a failure return either. This way we'll oops and get a backtrace. Signed-off-by: Bjorn Helgaas <bhelgaas@google.com>
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6b13672469
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1452cd76a9
@ -729,9 +729,9 @@ EXPORT_SYMBOL_GPL(pci_sriov_migration);
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*/
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int pci_num_vf(struct pci_dev *dev)
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{
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if (!dev || !dev->is_physfn)
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if (!dev->is_physfn)
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return 0;
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else
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return dev->sriov->num_VFs;
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}
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EXPORT_SYMBOL_GPL(pci_num_vf);
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@ -750,7 +750,7 @@ EXPORT_SYMBOL_GPL(pci_num_vf);
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*/
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int pci_sriov_set_totalvfs(struct pci_dev *dev, u16 numvfs)
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{
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if (!dev || !dev->is_physfn || (numvfs > dev->sriov->total_VFs))
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if (!dev->is_physfn || (numvfs > dev->sriov->total_VFs))
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return -EINVAL;
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/* Shouldn't change if VFs already enabled */
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@ -773,12 +773,12 @@ EXPORT_SYMBOL_GPL(pci_sriov_set_totalvfs);
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*/
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int pci_sriov_get_totalvfs(struct pci_dev *dev)
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{
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if (!dev || !dev->is_physfn)
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if (!dev->is_physfn)
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return -EINVAL;
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if (dev->sriov->driver_max_VFs)
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return dev->sriov->driver_max_VFs;
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else
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return dev->sriov->total_VFs;
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}
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EXPORT_SYMBOL_GPL(pci_sriov_get_totalvfs);
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