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rcu: Mark init-time-only rcu_bootup_announce() as __init
Because rcu_bootup_announce() is used only at boot time, mark it as __init, presumably so that its memory can be reclaimed. Suggested-by: Joe Perches <joe@perches.com> Signed-off-by: Paul E. McKenney <paulmck@linux.vnet.ibm.com> Cc: laijs@cn.fujitsu.com Cc: dipankar@in.ibm.com Cc: mathieu.desnoyers@polymtl.ca Cc: josh@joshtriplett.org Cc: dvhltc@us.ibm.com Cc: niv@us.ibm.com Cc: peterz@infradead.org Cc: rostedt@goodmis.org Cc: Valdis.Kletnieks@vt.edu Cc: dhowells@redhat.com LKML-Reference: <20091111192806.GA10073@linux.vnet.ibm.com> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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@ -33,7 +33,7 @@ DEFINE_PER_CPU(struct rcu_data, rcu_preempt_data);
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/*
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* Tell them what RCU they are running.
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*/
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static void rcu_bootup_announce(void)
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static void __init rcu_bootup_announce(void)
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{
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printk(KERN_INFO
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"Experimental preemptable hierarchical RCU implementation.\n");
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@ -481,7 +481,7 @@ void exit_rcu(void)
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/*
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* Tell them what RCU they are running.
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*/
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static void rcu_bootup_announce(void)
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static void __init rcu_bootup_announce(void)
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{
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printk(KERN_INFO "Hierarchical RCU implementation.\n");
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}
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