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perf: Fix default aux_watermark calculation
[ Upstream commit43deb76b19
] The default aux_watermark is half the AUX area buffer size. In general, on a 64-bit architecture, the AUX area buffer size could be a bigger than fits in a 32-bit type, but the calculation does not allow for that possibility. However the aux_watermark value is recorded in a u32, so should not be more than U32_MAX either. Fix by doing the calculation in a correctly sized type, and limiting the result to U32_MAX. Fixes:d68e6799a5
("perf: Cap allocation order at aux_watermark") Signed-off-by: Adrian Hunter <adrian.hunter@intel.com> Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Link: https://lore.kernel.org/r/20240624201101.60186-7-adrian.hunter@intel.com Signed-off-by: Sasha Levin <sashal@kernel.org>
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@ -684,7 +684,9 @@ int rb_alloc_aux(struct perf_buffer *rb, struct perf_event *event,
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* max_order, to aid PMU drivers in double buffering.
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*/
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if (!watermark)
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watermark = nr_pages << (PAGE_SHIFT - 1);
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watermark = min_t(unsigned long,
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U32_MAX,
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(unsigned long)nr_pages << (PAGE_SHIFT - 1));
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/*
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* Use aux_watermark as the basis for chunking to
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