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btrfs-progs: check: Fix wrong level access

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There's no reason to assume that the bad key order is in a leaf block,
so accessing level 0 of the path is going to be an error if it's actually
a node block that's bad.

Reported-by: Chris Mason <clm@fb.com>
Signed-off-by: Hugo Mills <hugo@carfax.org.uk>
Signed-off-by: David Sterba <dsterba@suse.cz>
This commit is contained in:
Hugo Mills 2014-05-05 18:07:49 +01:00 committed by David Sterba
parent 8efdd3ca4c
commit b5fc0b9014
1 changed files with 6 additions and 4 deletions
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10
cmds-check.c
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@ -2418,6 +2418,7 @@ static int try_to_fix_bad_block(struct btrfs_trans_handle *trans,
struct btrfs_path *path;
struct btrfs_key k1, k2;
int i;
int level;
int ret;
if (status != BTRFS_TREE_BLOCK_BAD_KEY_ORDER)
@ -2435,9 +2436,10 @@ static int try_to_fix_bad_block(struct btrfs_trans_handle *trans,
if (!path)
return -EIO;
path->lowest_level = btrfs_header_level(buf);
level = btrfs_header_level(buf);
path->lowest_level = level;
path->skip_check_block = 1;
if (btrfs_header_level(buf))
if (level)
btrfs_node_key_to_cpu(buf, &k1, 0);
else
btrfs_item_key_to_cpu(buf, &k1, 0);
@ -2448,9 +2450,9 @@ static int try_to_fix_bad_block(struct btrfs_trans_handle *trans,
return -EIO;
}
buf = path->nodes[0];
buf = path->nodes[level];
for (i = 0; i < btrfs_header_nritems(buf) - 1; i++) {
if (btrfs_header_level(buf)) {
if (level) {
btrfs_node_key_to_cpu(buf, &k1, i);
btrfs_node_key_to_cpu(buf, &k2, i + 1);
} else {